Proof: Inequality |a-c| <= |b-d|

[nhrock3]

prof that if a=<b and c=<d is given than |a-c|=<|b-d|
from the sum of the given we get a+c=<b+d
that as far as i went

 

[tiny-tim]

hi nhrock3!

(have a ≤ )

prof that if a=<b and c=<d is given than |a-c|=<|b-d|

that's obviously not true …

9 ≤ 10 and 1 ≤ 3

but 9 - 1 > 10 - 3