Proof: Inequality |a-c| <= |b-d|

  • Thread starter Thread starter nhrock3
  • Start date Start date
  • Tags Tags
    Proof
Click For Summary
SUMMARY

The discussion centers on the mathematical proof of the inequality |a-c| ≤ |b-d| under the conditions a ≤ b and c ≤ d. Participants debate the validity of this assertion, highlighting a counterexample where 9 ≤ 10 and 1 ≤ 3, yet |9-1| = 8 is greater than |10-3| = 7. The conclusion drawn is that the initial claim is not universally true, as demonstrated by the provided counterexample.

PREREQUISITES
  • Understanding of absolute value properties
  • Familiarity with basic inequalities
  • Knowledge of mathematical proof techniques
  • Ability to construct and analyze counterexamples
NEXT STEPS
  • Study the properties of absolute values in inequalities
  • Learn about constructing mathematical proofs
  • Explore advanced inequality theorems, such as the Triangle Inequality
  • Investigate common counterexamples in mathematical proofs
USEFUL FOR

Mathematicians, students studying inequalities, educators teaching proof techniques, and anyone interested in mathematical reasoning and logic.

nhrock3
Messages
403
Reaction score
0
prof that if a=<b and c=<d is given than |a-c|=<|b-d|
from the sum of the given we get a+c=<b+d
that as far as i went
 
Physics news on Phys.org
hi nhrock3! :smile:

(have a ≤ :wink:)
nhrock3 said:
prof that if a=<b and c=<d is given than |a-c|=<|b-d|

that's obviously not true …

9 ≤ 10 and 1 ≤ 3

but 9 - 1 > 10 - 3
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
0
Views
1K