Proof of Abelian Property - a * b * c = e

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Homework Help Overview

The discussion revolves around a group theory problem involving the abelian property of a binary operation within a group G. The original poster presents a statement where the product of three group elements results in the identity element, and the task is to show that a different arrangement of those elements also yields the identity.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the implications of assuming the group is abelian and discuss the validity of the original poster's reasoning. There is a focus on the associative law and its relevance to the problem. Questions are raised about the meaning of the equation a * (b * c) = e and the nature of the elements involved.

Discussion Status

The discussion is active, with participants providing insights and questioning assumptions. Some guidance has been offered regarding the use of the associative property and the implications of the binary operation, though no consensus has been reached on the approach to take.

Contextual Notes

There is an emphasis on the need to avoid assuming the group is abelian, as the problem does not specify this. Participants are also considering the properties of elements resulting from the binary operation.

jeff1evesque
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Statement:
37. Let G be a group and suppose that [tex]a * b * c = e[/tex] for [tex]a, b, c \in G.[/tex]

Problem:
Show that [tex]b * c * a = e.[/tex]

Thought Process
Can we assume that our binary operator [tex]*[/tex] is abelian. Thus, [tex]a * b * c = a * (b * c) = (b * c) * a = b * c * a.[/tex]

Thanks,

JL
 
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Hi jeff1evesque,

You can't assume the group is abelian when the question doesn't say it is abelian. Actually, the result is true even if the group is not abelian.
The associative law is helpful. can you state in plain english what a*(b*c) = e means?
 
winter85 said:
Hi jeff1evesque,

You can't assume the group is abelian when the question doesn't say it is abelian. Actually, the result is true even if the group is not abelian.
The associative law is helpful. can you state in plain english what a*(b*c) = e means?

It means that the binary operation on the three elements a, b, c produces the identity. Many possibilities can be true, depending on what the binary operator does. One possibility could be that the result of some operation between any of the two elements (a, b, c) yields to some element say r. When we take the operation of r with the third element we get the identity. There may however, be other possibilities (since the operation itself is undefined) which produces the same identity element [tex]e[/tex].
 
jeff1evesque said:
Statement:
37. Let G be a group and suppose that [tex]a * b * c = e[/tex] for [tex]a, b, c \in G.[/tex]

Problem:
Show that [tex]b * c * a = e.[/tex]

Here's an idea that is (I think) different from winter85's, even though that way would work too.

First multiply both sides of [tex]a * b * c = e[/tex] by a cleverly chosen element. "Repeat" as necessary, but not necessarily with the same element.

To receive full credit for your write-up, just take care that you left-multiply both sides, or right-multiply both, but don't left-multiply one side and right-multiply the other.
 
jeff1evesque said:
It means that the binary operation on the three elements a, b, c produces the identity. Many possibilities can be true, depending on what the binary operator does. One possibility could be that the result of some operation between any of the two elements (a, b, c) yields to some element say r. When we take the operation of r with the third element we get the identity. There may however, be other possibilities (since the operation itself is undefined) which produces the same identity element [tex]e[/tex].

if you let q = (b*c), the you have a*q = e.. what is q called in this case, with respect to a? what are its properties?
 

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