- #1

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I thought that I could show the [itex]n^{th}[/itex] term was greater than [itex]\frac{1}{n}[/itex] but this is turning out to be more difficult than I imagined. Is there a neat proof that [itex]n^n>(n+1)^{n-1}[/itex]?

- Thread starter Arkuski
- Start date

- #1

- 40

- 0

I thought that I could show the [itex]n^{th}[/itex] term was greater than [itex]\frac{1}{n}[/itex] but this is turning out to be more difficult than I imagined. Is there a neat proof that [itex]n^n>(n+1)^{n-1}[/itex]?

- #2

Dick

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