Proof of Electromagnetic Identity: Puzzling Last Expression

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SUMMARY

The discussion centers on the proof of an electromagnetic identity, specifically addressing the line integral of the differential volume element, dV. The integral along a curve, denoted as ##\Gamma##, with endpoints ##p## and ##q##, is evaluated as $$\int_\Gamma dV = \int_0^1 \frac{dV}{dt} dt$$. The participants clarify that the integral evaluates to zero under certain conditions, prompting a deeper inquiry into the completeness of the explanation provided. The intention behind the incomplete explanation is confirmed to stimulate critical thinking.

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larginal
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Homework Statement
two identities in electromagentics
Relevant Equations
curl of gradientV = 0
question.jpg

I tried to understand proof of this identity from electromagnetics. but I was puzzled at the last expression.
why is that line integral of dV = 0 ?
In fact, I'm wondering if this expression makes sense.
 
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If you had a curve integral along a curve ##\Gamma## with endpoints ##p## and ##q##, what would the integral
$$
\int_\Gamma dV
$$
be? Note that
$$
\int_\Gamma dV = \int_0^1 \frac{dV}{dt} dt
$$
if we assume that ##t## is a curve parameter in the interval [0,1] parametrising the curve such that ##p = \Gamma(0)## and ##q = \Gamma(1)##.
 
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I got it. Thanks! is it your intention that you didn't complete the explanation to make me think?
 
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larginal said:
is it your intention that you didn't complete the explanation to make me think?
Yes.
 
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