Proof of Electromagnetic Identity: Puzzling Last Expression

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Homework Help Overview

The discussion revolves around a proof related to an identity in electromagnetics, specifically focusing on a puzzling expression involving a line integral of \(dV\) and its implications.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the meaning of the line integral of \(dV\) and question why it equals zero. There is a reference to parametrizing the curve for better understanding.

Discussion Status

Some participants are engaging in clarifying the reasoning behind the integral, while others express curiosity about the intent behind the level of detail provided in the explanation. There is an acknowledgment of the need for deeper thinking without reaching a consensus.

Contextual Notes

There is a suggestion that the discussion may be influenced by the original poster's uncertainty about the expression's validity and the completeness of the explanation provided by others.

larginal
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Homework Statement
two identities in electromagentics
Relevant Equations
curl of gradientV = 0
question.jpg

I tried to understand proof of this identity from electromagnetics. but I was puzzled at the last expression.
why is that line integral of dV = 0 ?
In fact, I'm wondering if this expression makes sense.
 
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If you had a curve integral along a curve ##\Gamma## with endpoints ##p## and ##q##, what would the integral
$$
\int_\Gamma dV
$$
be? Note that
$$
\int_\Gamma dV = \int_0^1 \frac{dV}{dt} dt
$$
if we assume that ##t## is a curve parameter in the interval [0,1] parametrising the curve such that ##p = \Gamma(0)## and ##q = \Gamma(1)##.
 
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I got it. Thanks! is it your intention that you didn't complete the explanation to make me think?
 
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larginal said:
is it your intention that you didn't complete the explanation to make me think?
Yes.
 
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