Proof of Equality for B=Int(B)∪bd(B) in Metric Space A

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Homework Help Overview

The discussion revolves around the properties of compact subsets within a metric space, specifically examining the relationship between a set B, its interior Int(B), and its boundary bd(B). Participants are questioning the validity of the equality B = Int(B) ∪ bd(B).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of compactness and closedness of sets in metric spaces, questioning how these properties relate to boundary points and limit points.

Discussion Status

The discussion is ongoing, with participants raising questions about the definitions and properties of boundary points in relation to closed sets. There is an exploration of the implications of compactness in metric spaces, but no consensus has been reached.

Contextual Notes

Participants note that in metric spaces, compact sets are closed, which may influence the understanding of boundary points. The discussion also touches on the nature of Hausdorff spaces, which is relevant to the properties being examined.

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Let A be a metric space and B be a compact subset of A.
Is it true that an equality B = Int(B) [itex]\cup[/itex] bd(B) holds??
 
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In a metric space every compact set is closed (actually in every topological space). What does that tell you about its boundary points?
 
Boundary point is also limit point, right?
Then it belongs to B since B is closed?
 
HallsofIvy said:
In a metric space every compact set is closed (actually in every topological space).

Hausdorff topological space, no? Which does include metric spaces, I admit.
 

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