Proof of A Union of A Intersection B Equals A

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Homework Help Overview

The discussion revolves around proving the set equality ##A \cup (A \cap B) = A##. Participants are exploring the implications of set operations and the relationships between sets A and B.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants attempt to verify their proofs and question the validity of a teacher's proof that relies on the assumption ##A \subseteq B##. Others explore the logical implications of set intersections and unions, particularly questioning whether the teacher's reasoning is correct without this assumption.

Discussion Status

Participants are actively engaging with the problem, with some suggesting that the teacher's proof may be flawed due to unstated assumptions. There is a recognition of the need to clarify the relationship between sets A and B, and some participants are offering insights into the proof structure without reaching a consensus.

Contextual Notes

There is an ongoing discussion about the implications of the assumption ##A \cap B \subseteq A## and how it relates to the proof. Participants express uncertainty about the teacher's intent and the validity of their own reasoning.

member 587159

Homework Statement



Prove that ##A \cup (A \cap B) = A##

Homework Equations



In the previous exercise, we proved:

Let A, B be sets. Then, the following statements are equivalent:

1) ##A \subseteq B##
2) ##A \cup B = B##
3) ##A \cap B = A##

The Attempt at a Solution



The proof of ##A \cup (A \cap B) = A## according to the teacher was: we can use this previous exercise to show that ##A \cap B = A## Then the problem becomes that ##A \cup (A \cap B) = A \cap A = A##

However, we are not given that ##A \subseteq B##. Hence, we cannot apply this previous exercise. So, is the teacher's proof wrong?

Btw, can someone verify my proof:

Proof:

To show that ##A \cup (A \cap B) = A##, we show that ##A \cup (A \cap B) \subseteq A \land A \subseteq A \cup (A \cap B)##

1) Take ##x \in A \Rightarrow x\in A \cup (A \cap B)## by definition of union.
We deduce that ##A \subseteq A \cup (A \cap B)##

2) Take ##x \in A \cup (A \cap B) \Rightarrow x \in A \lor x \in A \cap B##
##\Rightarrow x \in A \lor (x \in A \land x \in B)##
##\Rightarrow x \in A## (logic argument: ##p \lor (p \land q) \Rightarrow p##)
We deduce that ##A \cup (A \cap B) \subseteq A##

QED.
 
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Math_QED said:

Homework Statement



Prove that ##A \cup (A \cap B) = A##

Homework Equations



In the previous exercise, we proved:

Let A, B be sets. Then, the following statements are equivalent:

1) ##A \subseteq B##
2) ##A \cup B = B##
3) ##A \cap B = A##

The Attempt at a Solution



The proof of ##A \cup (A \cap B) = A## according to the teacher was: we can use this previous exercise to show that ##A \cap B = A## Then the problem becomes that ##A \cup (A \cap B) = A \cap A = A##However, we are not given that ##A \subseteq B##. Hence, we cannot apply this previous exercise. So, is the teacher's proof wrong?

What do you think?
 
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PeroK said:
What do you think?

I think he's wrong. Can you verify the proof that I made please? (I edited my post)
 
Math_QED said:
I think he's wrong. Can you verify the proof that I made please? (I edited my post)

I think your teacher might have meant ##A \cap B \subseteq A## hence ##A \cup (A \cap B) = A##

Your proof looks a bit over-elaborate to me.
 
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PeroK said:
I think your teacher might have meant ##A \cap B \subseteq A## hence ##A \cup (A \cap B) = A##

Your proof looks a bit over-elaborate to me.

I'm not sure what the teacher meant. Next time I'll see him I'll ask what he meant. Thanks for your help.
 
Math_QED said:

Homework Statement



Prove that ##A \cup (A \cap B) = A##

Homework Equations



In the previous exercise, we proved:

Let A, B be sets. Then, the following statements are equivalent:

1) ##A \subseteq B##
2) ##A \cup B = B##
3) ##A \cap B = A##

The Attempt at a Solution



The proof of ##A \cup (A \cap B) = A## according to the teacher was: we can use this previous exercise to show that ##A \cap B = A## Then the problem becomes that ##A \cup (A \cap B) = A \cap A = A##

However, we are not given that ##A \subseteq B##. Hence, we cannot apply this previous exercise. So, is the teacher's proof wrong?
You do know that ##A \cap B\subseteq A\,,\ ## Right?

The proof pretty much follows from there.
 
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SammyS said:
You do know that ##A \cap B\subseteq A\,,\ ## Right?

The proof pretty much follows from there.

Wow didn't see that. Guess that happens when it's late. Thanks!
 

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