Proof of Equation for Period of Spring: T = 2pi (root x)/(root a)

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Discussion Overview

The discussion revolves around the proof of the equation for the period of a spring, specifically T = 2π (√x)/(√a). Participants are examining the validity of the proof in the context of simple harmonic motion, comparing it to concepts from uniform circular motion.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant presents a proof involving centripetal acceleration and its relation to the period of a spring, suggesting that T = 2π (√x)/(√a).
  • Another participant challenges the proof, arguing that centripetal acceleration is not applicable in the context of an oscillating spring and suggests using the formula T = 2(π)/f instead.
  • A third participant notes that both uniform circular motion and ideal spring motion are examples of simple harmonic motion, implying a connection between the two.
  • A later reply acknowledges the relationship between oscillating motion and circular motion but emphasizes that the proof should focus solely on the spring system to be considered valid for academic purposes.

Areas of Agreement / Disagreement

Participants express disagreement regarding the validity of the proof. Some argue that the use of centripetal acceleration is inappropriate, while others see a connection between circular and oscillatory motion. The discussion remains unresolved as no consensus is reached on the proof's correctness.

Contextual Notes

Limitations include the dependence on the definitions of motion types and the appropriateness of using concepts from circular motion in the proof for spring oscillation. The proof's acceptance may vary based on the context of the discussion.

decamij
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I just want to know if the following proof is okay. I'm in grade 12, and i this will probably be on my midterm.

Prove the following equation (for the period of a spring):

T = 2pi x (root)x/(root)a

If: ac=v^2/r, and v = 2pirf, then:

ac = 4pi^2rf^2, and:

ac = (4pi^2r)/T^2. Therefore,

T = root(4pi^2r)/a

Therefore,

T = 2pi (root x)/(root a)
 
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You equated it in a good manner but I don't thik it is good. You have taken centripetal acceleration in account but in an oscilating spring it is not possible.
To find it correctly, use t = 2 (pi)/f
find f for spring motion.
 
But something in uniform circular motion and an ideal spring are both examples of simple harmonic motion
 
yes, that's right, oscilating motion is also called as the projection of the circular motion. But when you are giving a proof for oscilating spring than you must take only spring i system in account, you can reffer to other relative systems, but relate them with the required system.
this proof is good to relate the circular motion and the oscillating motion but not good to obtain nice marks.
 

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