Proof of Kinematics Equation: Eliminating Time from the Equation

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SUMMARY

The discussion focuses on eliminating time from the kinematic equation (x - xi) = vi(t) + 1/2(a)t^2 to derive v^2 = vi^2 + 2a(x - xi) using the equation v = vi + at. A participant expresses confusion regarding the disappearance of the first term on the right side during their calculations. The conversation emphasizes the importance of understanding the manipulation of kinematic equations and the conditions under which terms may cancel out.

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PurelyPhysical
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Homework Statement



Eliminate t from the equation (x-xi)=vi(t)+1/2(a)t^2 using the kinematic equation v=vi+at to get
v^2=vi^2+2a(x-xi)

The Attempt at a Solution


I wind up with (x-xi)=vi(v-vi/a) + 1/2(v^2-vi^2/a). If the first term on the right side didn't exist, I could see what the solution is, but I can't see why it just seems to disappear.


here is a video showing the exact step where I get lost. Again, the first term on the right just disappears. I can see why that would happen if the initial velocity is 0, but what if it isn't?
 
Last edited:
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You've marked several places in the video. Not sure which step is bothering you.
It might be more useful to post your own working.
 

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