# Proof of Power Rule for 2 variables

ak123456

## Homework Statement

u^n (x,y)=nu^(n-1) (x,y) u' (x,y)

## The Attempt at a Solution

can i set f (x,y)=u^n (x,y)
lnf =lnu^n
lnf=nlnU
f'/f=n/U
f'=fn/U -(U(^n) )(n/U)
after that i don't know how to continue and is there a better way to prove it

Homework Helper

## Homework Statement

u^n (x,y)=nu^(n-1) (x,y) u' (x,y)
What do you mean by "u'(x,y)"? The gradient? The differential? "u' " is not defined for a function of two variables. If you mean the gradient, which is what I would think of as "the" derivative for a function of several variables, then yes, $\nabla u^n(x,y)= nu^{n-1}\nabla u$. That follows from the chain rule.

## The Attempt at a Solution

can i set f (x,y)=u^n (x,y)
lnf =lnu^n
lnf=nlnU
f'/f=n/U
f'=fn/U -(U(^n) )(n/U)
after that i don't know how to continue and is there a better way to prove it