Proof of Theorem (0.2): Questions to Ask

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The forum discussion centers on the proof of Theorem (0.2) and the conditions under which contradictions arise based on the behavior of the function f at a point x₀. Specifically, it addresses two scenarios: when f(x₀) < 0 and when f(x₀) > 0. The participants emphasize the importance of the definition of the set X, which includes all x in the interval [a, b] where f(x) ≤ 0, and the necessity of choosing δ sufficiently small to ensure the interval (x₀ - δ, x₀ + δ) remains within [a, b]. The mathematical expression for this condition is also discussed, particularly in relation to the supremum of X.

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solakis1
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for the theorem (0.2) attached i have the following questions to ask:

1) In the case where f(xo)<0 ,the author justifies the contradiction he comes to,by writing that :

"every xε [xo,xo+δ) belongs to X"

How can we prove that?

2) In the case where f(xo)>0 ,the author justifies the contradiction he comes to,by assming that:

(xo-δ) is an upper bound for X.

How can we prove that?
 

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Re: bolzano theorem

solakis said:
for the theorem (0.2) attached i have the following questions to ask:

1) In the case where f(xo)<0 ,the author justifies the contradiction he comes to,by writing that :

"every xε [xo,xo+δ) belongs to X"

How can we prove that?

2) In the case where f(xo)>0 ,the author justifies the contradiction he comes to,by assming that:

(xo-δ) is an upper bound for X.

How can we prove that?
Both these things come from the definition of $X$, which says that if $x\in[a,b]$ satisfies $f(x)\leqslant0$ then $x\in X$. (But note that in both cases the author seems to be assuming that $\delta$ has been chosen small enough so that the interval $(x_0-\delta,x_0+\delta)$ is contained in the interval $[a,b].$)
 
Re: bolzano theorem

Opalg said:
Both these things come from the definition of $X$, which says that if $x\in[a,b]$ satisfies $f(x)\leqslant0$ then $x\in X$. (But note that in both cases the author seems to be assuming that $\delta$ has been chosen small enough so that the interval $(x_0-\delta,x_0+\delta)$ is contained in the interval $[a,b].$)

yes,but how do you express mathematically the expression:

"$\delta$ has been chosen small enough so that the interval $(x_0-\delta,x_0+\delta)$ is contained in the interval $[a,b].$"
 
Re: bolzano theorem

Opalg said:
Both these things come from the definition of $X$, which says that if $x\in[a,b]$ satisfies $f(x)\leqslant0$ then $x\in X$. (But note that in both cases the author seems to be assuming that $\delta$ has been chosen small enough so that the interval $(x_0-\delta,x_0+\delta)$ is contained in the interval $[a,b].$)
O.K suppose he chooses delta small enough so that the interval $(x_0-\delta,x_0+\delta)$ is contained in the interval $[a,b].$".

Then how does he get : SupX $\geq\delta+x_{o}> x_{o}$
 

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