Proof: Product of Orthogonal Matrices is Orthogonal

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The discussion focuses on proving that the product of orthogonal matrices is orthogonal. Participants clarify that if matrices A and B are orthogonal, then their inverses satisfy A-1 = AT and B-1 = BT. The proof involves showing that (AB)-1 = (AB)T by using the property that (AB)-1 can be expressed as B-1A-1. The conversation highlights the importance of understanding matrix properties and their implications in linear algebra.

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soothsayer
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Homework Statement


Show that a product of orthogonal matrices is orthogonal.

Homework Equations


Orthoganol matrix: M-1=MT

The Attempt at a Solution


since A-1=AT
A-1 and AT commute.
commutable => symmetric => A-1AT=(A-1AT)T

(A-1AT)-1=A-1AT/det(A-1AT)
=> (A-1AT)-1(A-1AT)=(A-1AT)2/det(A-1AT)
M-1M=I
M2=-I
=> I=-I/det(A-1AT)=> det(A-1AT) = -1
=> (A-1AT)-1=-(A-1AT)
=> (A-1AT)-1=/=A-1AT ??
I'm sure I did something wrong here. Probably overstepped an assumption. Can anyone help?
 
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hi soothsayer! :smile:

i don't understand what you're trying to do :redface:

you have to prove that if A-1=AT and B-1=BT, then (AB)-1=(AB)T :wink:
 
Yes, I understand that, but what practical way do I have of proving that?
 
what's another way of writing (AB)-1 ? :wink:
 
Well, for orthoganol A and B, it would be = (AB)T and I believe you can also write it as B-1A-1, correct?
 
hi soothsayer! :smile:

(just got up :zzz: …)
tiny-tim said:
what's another way of writing (AB)-1 ? :wink:
soothsayer said:
… I believe you can also write it as B-1A-1, correct?

correct! :smile:

ok, now what's another way of writing (AB)T ? :wink: :wink:
 

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