Undergrad Proof Using Rearrangement Inequality

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SUMMARY

The Rearrangement Inequality asserts that for two sequences {a_i} and {b_i}, the sum S_n = ∑_{i=1}^n a_i b_i is maximized when both sequences are similarly ordered. This discussion applies the theorem to prove that for any three positive integers a, b, and c, the inequality $$\frac{a^2}{b^2} + \frac{b^2}{c^2} + \frac{c^2}{a^2} \geq \frac{b}{a} + \frac{a}{c} + \frac{c}{b}$$ holds true. The proof involves rewriting the terms to facilitate the application of the Rearrangement Inequality, specifically using a common denominator to simplify the expression.

PREREQUISITES
  • Understanding of the Rearrangement Inequality
  • Familiarity with sequences and summation notation
  • Basic knowledge of algebraic manipulation and exponents
  • Experience with inequalities in mathematics
NEXT STEPS
  • Study the applications of the Rearrangement Inequality in optimization problems
  • Explore advanced topics in inequalities, such as Cauchy-Schwarz and AM-GM inequalities
  • Learn about sequences and series in greater depth
  • Investigate algebraic techniques for manipulating fractions and common denominators
USEFUL FOR

Mathematicians, students studying inequalities, and anyone interested in advanced algebraic techniques and proofs.

James Brady
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The Rearrangement Inequality states that for two sequences ##{a_i}## and ##{b_i}##, the sum ##S_n = \sum_{i=1}^n a_ib_i## is maximized if ##a_i## and ##b_i## are similarly arranged. That is, big numbers are paired with big numbers and small numbers are paired with small numbers.

The question given is using the above theorem to to prove that for any given three positive whole numbers a,b and c:

$$\frac{a^2}{b^2} + \frac{b^2}{c^2} + \frac{c^2}{a^2} \geq \frac{b}{a} + \frac{a}{c} + \frac{c}{b}$$

Thinking so far: the theorem deals with maximizing or minimizing the Cartesian product of sets, but we have denominators in each term, maybe I can rewrite the denominators using negative exponents...? But I don't see how that gets me any closer either, basically I need some kind of nudge in the right direction.​
 
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Hint:
\frac{b}{a}+\frac{a}{c} + \frac{c}{b} = \frac{b}{c}\frac{c}{a}+\frac{a}{b}\frac{b}{c}+\frac{a}{b}\frac{c}{a}
 
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Perfect, I used that to build a common denominator which then canceled out.
 

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