Prooving a projectile motion formula

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stonecoldgen
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Homework Statement



Two rocks are thrown from a cliff of height h at the same speed V0. One rock is thrown up at angle (Theta 1) adn the other is thrown down at angle (Theta 2). Show that both rocks hit the ground at the same speed.

V= (V0^2+2gh)^(.5)



Homework Equations



V'^2=V^2+2ad

d=vt+.5at^2


The Attempt at a Solution



well, logically it is really easy to solve. When the rock that is launched up comes back down to the level that the other rock is launched down out, it gets the same speed it was launched at (V0), and the other rock is V0 as well, so there you go.

I tried a solution with a quadratic formula but itt didnt work, somehow i see that if i proove the firsth equation in my list (formula 5 of the kinematic equations), from galileo's equation i might get something, but I am not sure how to do that.
 
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stonecoldgen said:

Homework Statement



Two rocks are thrown from a cliff of height h at the same speed V0. One rock is thrown up at angle (Theta 1) adn the other is thrown down at angle (Theta 2). Show that both rocks hit the ground at the same speed.

V= (V0^2+2gh)^(.5)



Homework Equations



V'^2=V^2+2ad

d=vt+.5at^2


The Attempt at a Solution



well, logically it is really easy to solve. When the rock that is launched up comes back down to the level that the other rock is launched down out, it gets the same speed it was launched at (V0), and the other rock is V0 as well, so there you go.

I tried a solution with a quadratic formula but itt didnt work, somehow i see that if i proove the firsth equation in my list (formula 5 of the kinematic equations), from galileo's equation i might get something, but I am not sure how to do that.

When the are "launched", they start from the same height - so same Potential energy per kg, and start at the same speed, so same kinetic energy per kg, so when they both get to ground level, how will their kinetic energy per kg compare, and what does that mean?
 
can you include a picture?