Propagation of Error and Relative Error

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SUMMARY

The discussion focuses on the propagation of error in projectile motion, specifically calculating the accuracy of range estimation when launching a projectile at a 30-degree angle with an initial velocity of 20 m/s. The student encounters difficulties in applying the cotangent function and understanding the importance of using radians instead of degrees for angle measurements. The final calculation yields a relative accuracy of 0.0302 when the angle is expressed in radians, emphasizing the necessity of consistent unit usage in trigonometric calculations.

PREREQUISITES
  • Understanding of projectile motion equations, specifically R = v²/g * sin(2θ)
  • Knowledge of derivatives in calculus, particularly for trigonometric functions
  • Familiarity with the concept of relative error and accuracy in measurements
  • Proficiency in unit conversions, especially between degrees and radians
NEXT STEPS
  • Learn about the derivation of projectile motion equations in physics
  • Study the application of derivatives in error propagation analysis
  • Explore the significance of using radians in trigonometric calculations
  • Investigate common pitfalls in unit conversions and how to avoid them
USEFUL FOR

Students in physics or engineering, educators teaching projectile motion concepts, and anyone involved in experimental design and error analysis in scientific research.

GoCubs12
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Homework Statement



2) A student is performing an angry bird experiment in real life. He calculates the range of the projectile by shooting the bird with a 30 degree angle and an initial velocity of v0 = 20 m/s.

a) If the relative accuracy of setting the projectile angle is delta theta/theta = 0.05, what would be the accuracy of the range estimation?

Homework Equations



delta R= derivative of range equation*delta theta

R=v^2/g*sin(2*theta)

The Attempt at a Solution



I determined the derivative of the range equation and got v^2/g*2*cos(2*theta). I then divided this by the original function and got delta x/x=2cot(2*theta)*delta theta. This is the point I am stuck at. Normally with the problems I have done so far I would get to this point and be able to substitute in the given value of delta theta/theta. However, the cot is throwing me for a loop and I just can't to find a way through it and past that point. All advice is appreciated. Thanks!
 
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What is your problem with cotangent? You lost sight of what you are suppose to be looking for but you are on the right track.
 
gleem said:
What is your problem with cotangent? You lost sight of what you are suppose to be looking for but you are on the right track.

My problem is that if I put theta into the cot and solve the relative accuracy of the angle for delta theta and put that into the equation as well, I get a number over 100% which doesn't seem like it is even remotely correct and I just can't think of any other way to go about it.
 
What value are you using for dθ?
 
gleem said:
What value are you using for dθ?

The only value I could think of was to solve dTheta/Theta for dTheta. So the value is really 30*0.05.
 
That is you problem. Can you figure out why? Think units.
 
gleem said:
That is you problem. Can you figure out why? Think units.

I know that the answer I am getting currently would be in degrees which is incorrect but I can't seem to find a way to solve for dTheta without it encountering that issue. Is there another way to figure out dTheta?
 
dθ = .05⋅θ What units should you be using for θ? What other unit for angles is there?
 
gleem said:
dθ = .05⋅θ What units should you be using for θ? What other unit for angles is there?

Using radians I get a final answer of 0.0302. How do you know you need to use radians instead of degrees though. I know that the answer seems more reasonable now but in the future how can I tell?
 
  • #10
GoCubs12 said:
Using radians I get a final answer of 0.0302. How do you know you need to use radians instead of degrees though. I know that the answer seems more reasonable now but in the future how can I tell?
If you take the derivative of a trig function the assumption is that the angle is expressed in radians. In those units, the first derivative of sine is cosine.

If you have a trig function and the angle is in degrees, you will need to insert a unit conversion factor of pi radians per 180 degrees each time you integrate or take a derivative.

It's usually easier to always do the math using radians and to convert the inputs and outputs as required.
 
  • #11
GoCubs12 said:
Using radians I get a final answer of 0.0302. How do you know you need to use radians instead of degrees though. I know that the answer seems more reasonable now but in the future how can I tell?

Always use radians. 1 deg = π/180 rad. When looking up values for trig functions where degrees is the specified unit of the table or calculator setting change radians to degrees using 1 rad. = 180/π deg. (verify your calculator setting)
 

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