Propagation of error if one of the values is 0

  • Thread starter Thread starter nietzsche
  • Start date Start date
  • Tags Tags
    Error Propagation
Click For Summary

Homework Help Overview

The discussion revolves around the propagation of error in a product involving a quantity that is zero. The original poster is attempting to understand how to apply the error propagation formula when one of the values being multiplied is zero.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of having a zero value in the error propagation formula, questioning whether it leads to a defined outcome or reflects measurement accuracy issues. There is also a reference to the role of partial derivatives in understanding the formula's behavior at zero.

Discussion Status

The discussion is ongoing, with participants providing insights into the mathematical implications of zero in the context of error propagation. Some guidance has been offered regarding the use of partial derivatives, although the original poster has not yet learned this concept.

Contextual Notes

The original poster mentions that the zero value pertains to the velocity of a cart measured by a motion sensor, indicating a specific experimental context. There is also a noted uncertainty in the measurement of this velocity.

nietzsche
Messages
185
Reaction score
0
I'm doing a lab write-up and I've run into a snag. I'm trying to do propagation of error in a product, but one of my quantities that I'm multiplying is 0. The propagation of error formula for z = xy is

[tex] \left ( \frac{\Delta z}{z} \right )^2 = \left( \frac{\Delta x}{x} \right )^2 + \left (\frac{\Delta y}{y} \right )^2[/tex]

But if either x or y = 0, what happens?
 
Physics news on Phys.org
Is it 0 by definition or is that just a measurement with low accuracy?
 
it's the velocity of a cart that was measured by a motion sensor, so it's a measurement. the value is 0.00 +/- 0.005.
 
If you look into the partial derivative definition used to find that error propagation formula, you will see that x = 0 makes the infinite term disappear. See
http://www.rit.edu/cos/uphysics/uncertainties/Uncertaintiespart2.html#muldiv
 
Last edited by a moderator:
thank you. i haven't learned partial derivatives yet, so i'll have to take your word for it.
 

Similar threads

Replies
15
Views
2K
  • · Replies 7 ·
Replies
7
Views
910
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
64
Views
6K