Undergrad Propagator operator in Heinsenberg picture

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SUMMARY

The propagator in the Heisenberg picture is represented by the expression ##<0|\phi(x)\phi(y)|0>##, where ##\phi## denotes the Klein-Gordon field. This expression is identified as the Wightman function and is distinct from the time-ordered propagator, which is the Feynman propagator given by ##\mathrm{i} \Delta_F(x)=\langle 0|T_c \hat{\phi}(x) \hat{\phi}(0) \rangle##. The discussion emphasizes the importance of distinguishing between different types of propagators and their roles in quantum field theory (QFT), particularly in relation to the S-matrix and causal descriptions of scattering events. The source of confusion arises from the misinterpretation of the Wightman function as a propagator without specifying its context and application.

PREREQUISITES
  • Understanding of quantum field theory (QFT) concepts
  • Familiarity with the Klein-Gordon field and its properties
  • Knowledge of the time evolution operator in quantum mechanics
  • Experience with Feynman and Wightman propagators
NEXT STEPS
  • Study the derivation of the Feynman propagator in vacuum QFT
  • Explore the Schwinger-Keldysh real-time-contour formalism
  • Learn about the Linked-Cluster Principle and its implications in QFT
  • Read S. Weinberg's "Quantum Theory of Fields, vol. 1" for advanced insights on propagators
USEFUL FOR

Quantum field theorists, physicists studying particle interactions, and advanced students seeking to deepen their understanding of propagators and their applications in QFT.

Silviu
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Hello! I read that in Heisenberg picture the propagator from x to y is given by ##<0|\phi(x)\phi(y)|0>##, where ##\phi## is the Klein-Gordon field. I am not sure I understand why. I tried to prove it like this:
##|x>=\phi(x,0)|0>## and after applying the time evolution operator we have ##U(t)|x>=e^{-iHt}\phi(x,0)|0>##. And the propagator should show the overlapping between ##|x>## and ##|y>## at time t. This would be
##<y|U(t)|x>=<0|\phi(y,0)e^{-iHt}\phi(x,0)|0> = <0|e^{-iHt}\phi(y,0)\phi(x,0)|0>## which is not what I was supposed to obtain. I am also not sure about the time dependence of ##\phi## in the propagator. Can someone explain this to me?
 
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Where have you read this? What you've written down is the Wightman function and one Green function in the Schwinger-Keldysh real-time-contour formalism. What's the purpose of this function in your context?

Usually in vacuum QFT you work with the time-ordered propagator (which in the vacuum is the same as the Feynman propagator), i.e.,
$$\mathrm{i} \Delta_F(x)=\langle 0|T_c \hat{\phi}(x) \hat{\phi}(0) \rangle,$$
where I assume the uncharged KG field (where ##\hat{\phi}=\hat{\phi}^{\dagger}##).
 
Last edited:
vanhees71 said:
Where have you read this? What you've written down is the Wightman function and one Green function in the Schwinger-Keldysh real-time-contour formalism. What's the purpose of this function in your context?

Usually in vacuum QFT you work with the time-ordered propagator (which in the vacuum is the same as the Feynman propagator), i.e.,
$$\mathrm{i} \Delta_F(x)=\langle 0|T_c \hat{\phi}(x) \phi{\phi}(0) \rangle,$$
where I assume the uncharged KG field (where ##\hat{\phi}=\hat{\phi}^{\dagger}##).
It is from Peskin book on QFT. On page 27 (at least this is what I understood, please let me know if that means something different)
 
Peskin and Schroeder are not always careful enough. However, here they give the resolution in the discussion on the following pages (see p. 29).
 
vanhees71 said:
Peskin and Schroeder are not always careful enough. However, here they give the resolution in the discussion on the following pages (see p. 29).
Wait I am confused. So what is wrong about this. Like what is this object ##<0|\phi(x) \phi(y)|0>##, if it is not a propagator? And how do they come up with it (as it seems to be the main tool for what follows)?
 
It is not enough to call something propagator but you have to specify which propagator it is. In the Feynman rules, leading to causal S-matrix elements it's not this propagator (a socalled Wightman function) that occurs but the time-ordered propagator. Usually you define the Wightman function by
$$\mathrm{i} \Delta_{12}(x)=\langle 0|\hat{\phi}(x) \hat{\phi}(0)| 0\rangle.$$
Then the time-ordered propagator (which for vacuum QFT is the Feynman propagator) is defined as
$$\mathrm{i} \Delta_{11}(x)=\mathrm{i} \Delta_{\text{F}}(x)=\langle 0|T_c \hat{\phi}(x) \hat{\phi}(0)|0 \rangle=\mathrm{i}[\Theta(x^0) \Delta_1(x)+\Theta(-x^0) \Delta_1(-x)].$$
As is worked out in Peskin&Schroeder, this leads to a causal description of scattering events in terms of the S-matrix. The trick is that you introduce antiparticles (in the case of the hermitean Klein-Gordon field you describe neutral scalar bosons, for which the particle and antiparticle are the same) in addition to particles to make everything causal, where causal means that local experiments that are separated by far distances lead to uncorrelated results for transition probabilities, the socalled "Linked-Cluster Principle". This is closely connected with the microcausality condition, which is realized by the vanishing of field-operator commutators (or anti-commutators for fermion fields) for space-like separated arguments, i.e., for the scalar field
$$[\hat{\phi}(x),\hat{\phi}(y)]=0 \quad \text{for} \quad (x-y)^2<0,$$
where my Minkowski product is defined by the west-coast convention, i.e., ##\eta_{\mu \nu}=\mathrm{diag}(1,-1,-1,-1)## as in Peskin&Schroeder. That's why Peskin&Schroeder proves that the vacuum expectation value of this field commutator vanishes for space-like separated arguments.

For a much more careful (but also rather more advanced) line of arguments concerning all these issues, see

S. Weinberg, Quantum Theory of Fields, vol. 1, Cambridge University Press
 

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