Properties of cross and dot products

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If u is a nonzero vector and u.v = u.w and u x v = u x w, it can be concluded that v = w. The reasoning is based on the properties of dot and cross products, where both conditions imply that the vector (v - w) is orthogonal to u and also parallel to u. Since u is not the zero vector, this leads to the conclusion that (v - w) must be the zero vector, thus v equals w. The argument is validated by the relationship between the dot and cross products in vector analysis.
bobey
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Homework Statement


let u be a nonzero vector in space and let v and w be any two vectors in space. if u.v = u.w and u x v = u x w, can you conclude that v=w? give reason for your answer.


Homework Equations





The Attempt at a Solution


v is not necessary equal to w
since u is nonzero vector thus the cross product of the vector u with v and w will produce another vector and it is consider the same theirs magnitude and directions are same and their dot product will produce a scalar which has no indication of direction. thus v and w is not necessary same vector.

is my argument is true... or can anyone improve it and prove it with example... your help is highly appreciated... thanx
 
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bobey said:

Homework Statement


let u be a nonzero vector in space and let v and w be any two vectors in space. if u.v = u.w and u x v = u x w, can you conclude that v=w? give reason for your answer.


Homework Equations





The Attempt at a Solution


v is not necessary equal to w
since u is nonzero vector thus the cross product of the vector u with v and w will produce another vector and it is consider the same theirs magnitude and directions are same and their dot product will produce a scalar which has no indication of direction. thus v and w is not necessary same vector.

is my argument is true... or can anyone improve it and prove it with example... your help is highly appreciated... thanx
I have no clue what that means. You start by saying v is not necessarily the same as w, say a couple of general things about cross product and dot product and conclude that v and w are not necessarily the same. What, in what you said about cross product and dot product, led to that conclusion? When you say " it is consider the same their magnitude and directions are same" what vectors are you talking about having the same magnitude and direction? What does "their" refer to?
I think you would be better off using specific formulas. In particular I would recommend using the fact that u\cdot v= |u||v|cos(\theta) and |u\times v|= |u||v| sin(\theta).

It will help to know that for \theta and \phi both between 0 and 180 degrees, tan(\theta)= tan(\phi) implies \theta= \phi.
 
HallsofIvy said:
I have no clue what that means. You start by saying v is not necessarily the same as w, say a couple of general things about cross product and dot product and conclude that v and w are not necessarily the same. What, in what you said about cross product and dot product, led to that conclusion? When you say " it is consider the same their magnitude and directions are same" what vectors are you talking about having the same magnitude and direction? What does "their" refer to?
I think you would be better off using specific formulas. In particular I would recommend using the fact that u\cdot v= |u||v|cos(\theta) and |u\times v|= |u||v| sin(\theta).

It will help to know that for \theta and \phi both between 0 and 180 degrees, tan(\theta)= tan(\phi) implies \theta= \phi.

why you think to use this fact : u\cdot v= |u||v|cos(\theta) and |u\times v|= |u||v| sin(\theta) in your arguments? I CAN'T SEE IT!

this is my new argument ::

yes v = w.
u.v = v.u and u x v = u x w implies that u.(v-w)=0 and u x (v-w) = 0 implies that u perpendicular with (v-w) and u parallel to (v-w) implies that u = 0 or (v-w) = 0

thus v=w since u is not a zero vectorIS MY ARGUMENT CORRECT NOW? or any other ideas...THANX 4 D RESPONSE HallsofIvy... :-p
 
Yes, that is right.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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