Prove 1-n^2>0, Then 3n-2 is Even | Math Homework Help

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Homework Help Overview

The problem involves proving that for an integer \( n \), if \( 1 - n^2 > 0 \), then \( 3n - 2 \) is an even integer. The context is within introductory proof techniques in mathematics.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • One participant attempts to prove the statement by substituting \( n = 0 \) and concluding that \( 3n - 6 \) is even. Others question the clarity of the problem statement and suggest rephrasing for better understanding.

Discussion Status

Participants are exploring different interpretations of the problem and discussing the clarity of the wording. Some guidance on the nature of the problem and its placement in the forum has been offered, but no consensus on a solution has been reached.

Contextual Notes

There are indications of confusion regarding the problem's classification within mathematical topics, with suggestions to consider different sections of the forum for posting.

bonfire09
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Homework Statement



Let nεZ,Prove that 1-n^2>0, then 3n-2 is an even integer.

Homework Equations


The Attempt at a Solution



I proved it like this. I think its right but I am not able to word it correctly.

Since 1-n^2>0 therefore n=0. Then 3n-6=3(0)-6=-6. Since 0 is an integer, 3n-6 is even.

How can I learn to word this correctly because I am having some trouble with it?
 
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Try posting in the number theory forum, this isn't really calculus.
 
this is intro to proofs actually. I am trying to self study.
 
I wouldn't worry too much about proper wording as long as you get the concept. n has to equal zero and -6 is an even integer...sounds proved to me. :)

Although, you probably shouldn't take my advice. I'm shunned by many in academia due to my deep detestation of pretentiousness. ;)
 
bonfire09 said:

Homework Statement



Let nεZ,Prove that 1-n^2>0, then 3n-2 is an even integer.
The above is confusing. A better statement would be
Let n ##\in## Z. If 1 - n2 > 0, then show that 3n - 2 is an even integer.
bonfire09 said:

The Attempt at a Solution



I proved it like this. I think its right but I am not able to word it correctly.

Since 1-n^2>0 therefore n=0. Then 3n-6=3(0)-6=-6. Since 0 is an integer, 3n-6 is even.

How can I learn to word this correctly because I am having some trouble with it?
Note that you have a typo in your work. You're supposed to prove that 3n - 2 is an even integer.

I would say it like this:
Since 1 - n2 > 0 and n ##\in## Z, then n = 0.
So 3n - 2 = - 2, which is an even integer.

Therefore, for any integer n, if 1 - n2 > 0, then 3n - 2 is an even integer.

Whovian said:
Try posting in the number theory forum, this isn't really calculus.
It should NOT be posted in the number theory section. That section and the other sections under Mathematics are not for homework and homework-type problems

Whovian said:
No, here is probably fine, although the Precalc Mathematics section would also be a good choice.
 

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