Lonewolf Messages 329 Reaction score 1 Apr 20, 2005 #31 So, if I chose another symbol for 1, its numerical value would change?
krypto Messages 14 Reaction score 0 Apr 20, 2005 #32 nope cos it still means 1 even if u named it bob
Lonewolf Messages 329 Reaction score 1 Apr 20, 2005 #33 Precisely. So writing 0.999... shouldn't falsify 0.999... = 1, right?
gregmead Messages 42 Reaction score 0 Apr 20, 2005 #34 A recurring decimal can be written like: [tex]S = A*r^n[/tex] [tex]0.999... = 0.9*0.1^n[/tex] Sum to infinity of a converging series: [tex]\frac {A}{1-r}[/tex] So, [tex]\frac {0.9}{1-0.1}=\frac {0.9}{0.9} = 1[/tex]
A recurring decimal can be written like: [tex]S = A*r^n[/tex] [tex]0.999... = 0.9*0.1^n[/tex] Sum to infinity of a converging series: [tex]\frac {A}{1-r}[/tex] So, [tex]\frac {0.9}{1-0.1}=\frac {0.9}{0.9} = 1[/tex]
The Rev Messages 81 Reaction score 0 Apr 20, 2005 #35 It's times like this that we need to consider switching to a duodecimal system. In duodecimal 1/3 = 0.4 Much easier. [tex]\sigma[/tex] The Rev
It's times like this that we need to consider switching to a duodecimal system. In duodecimal 1/3 = 0.4 Much easier. [tex]\sigma[/tex] The Rev
Hurkyl Staff Emeritus Science Advisor Gold Member Messages 14,922 Reaction score 28 Apr 20, 2005 #36 Well, since nobody seems to be learning anything, I'll close it up.