Prove A=B when A⊂span(B) and B⊂span(A)

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SUMMARY

In the discussion, it is established that if subsets A and B of a vector space V satisfy A ⊂ span(B) and B ⊂ span(A), then it follows that span(A) = span(B). The proof involves demonstrating that since A is contained in the span of B, the span of A must also be contained in the span of B, and vice versa. This leads to the conclusion that the spans of A and B are equal, thus confirming the relationship between the two subsets.

PREREQUISITES
  • Understanding of vector spaces and their properties
  • Familiarity with the concept of span in linear algebra
  • Knowledge of subset relations in mathematical contexts
  • Basic proof techniques in mathematics
NEXT STEPS
  • Study the properties of vector spaces in linear algebra
  • Learn about the concept of span and its implications
  • Explore the relationship between subspaces and their spans
  • Practice mathematical proof techniques, particularly in linear algebra
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Students of linear algebra, mathematicians, and anyone interested in understanding the relationships between subsets and spans in vector spaces.

toni07
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Let A and B be subsets of a vector space V. Assume that A ⊂ span(B) and that B ⊂ span(A) Prove that A = B.
I don't know how to go about this question, any help would be appreciated.
 
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crypt50 said:
Let A and B be subsets of a vector space V. Assume that A ⊂ span(B) and that B ⊂ span(A) Prove that A = B.

That is not true. Choose for example $V=\mathbb{R}^2,$ $A=\{(1,0)\}$ and $B=\{(2,0)\}.$
 
crypt50 said:
Let A and B be subsets of a vector space V. Assume that A ⊂ span(B) and that B ⊂ span(A) Prove that A = B.
I don't know how to go about this question, any help would be appreciated.
Quite likely what you were actually after is the following:

If $A\subseteq\text{ span}(B)$ and $B\subseteq\text{ span}(A)$, then $\text{span}(A)=\text{span}(B)$.

Let $\text{span}(A)=U$ and $\text{span}(B)=W$.

Since $A\subseteq W$, we have $\text{span}(A)=U\subseteq W$. This is because $W$ is a subspace of $V$. Similarly $W\subseteq U$. We get $W=U$ and we are done.
 

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