Prove rms voltage using integration

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SUMMARY

The discussion focuses on proving that the root-mean-square (RMS) voltage of the AC voltage function \( v = \sin x \) is 0.707 volts through integration. The RMS value is defined as the square root of the average of the square of the function over a specified interval. The relevant formula for calculating the average of the square of a function \( f(x) \) is given by \( \frac{\int_{t_{1}}^{t_{2}} (f(x))^{2} dx}{t_{2} - t_{1}} \). Participants are encouraged to perform the integration for \( f(x) = \sin x \) to arrive at the RMS value.

PREREQUISITES
  • Understanding of root-mean-square (RMS) calculations
  • Familiarity with integration techniques
  • Knowledge of sinusoidal functions
  • Basic calculus concepts
NEXT STEPS
  • Perform integration of \( \sin^2 x \) over the interval [0, π] to calculate RMS voltage
  • Explore the derivation of RMS values for other sinusoidal functions
  • Study the application of RMS voltage in electrical engineering
  • Learn about the differences between RMS and average voltage calculations
USEFUL FOR

Students in electrical engineering, physics learners, and anyone interested in understanding the mathematical proof of RMS voltage for sinusoidal functions.

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Homework Statement



ac voltage
v=sinx



Homework Equations



how do you prove that rms voltage is 0.707v using integration

The Attempt at a Solution

 
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The root-mean-square value of a function is the root of the average of the square of the function.
The average of the square of a function f (x) over an interval is given by:
\frac{\int_{t_{1}}^{t_{2}} (f (x))^{2} dx}{t_{2} - t_{1}}​
You can do the relevant integration yourself for f (x) = sin x (or any sinusoidal function for that matter)
 

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