Prove sinh(z) Identity: Show |sinh(z)|^2 = sin^2x + sinh^2y

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The identity |sinh(z)|^2 = sin^2(x) + sinh^2(y) has been confirmed and simplified using the relationships cos(iy) = cosh(y) and sin(iy) = i sinh(y). A correction was noted regarding a potential typo, suggesting the identity should be |sinh(z)|^2 = sinh^2(x) + sin^2(y) for accuracy. This discussion highlights the importance of understanding hyperbolic and trigonometric functions in complex analysis.

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Show $ |sinh(z)|^2 = sin^2x + sinh^2y $
Since I posted this, I found new info - cos(iy) = cosh(y) and sin(iy) = i sinh(y) which made the above easy; don't want to bother anyone so will mark this solved.
 
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ognik said:
Show $ |sinh(z)|^2 = sin^2x + sinh^2y $
Since I posted this, I found new info - cos(iy) = cosh(y) and sin(iy) = i sinh(y) which made the above easy; don't want to bother anyone so will mark this solved.

Hey ognik,

Just for the record, it appears there is a typo in there.
It should be for instance
$$ |\sinh(z)|^2 = \sinh^2x + \sin^2y $$
otherwise it's not true. :eek:
 

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