- #1
Mr.Tibbs
- 24
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Hey all, I want to prove that a function is periodic using the formula:
x(t) = x(t+T)
where T is the supposed period.An example equation would be:
x(t) = 7sin(3t)
I would set up the equation like so:
7sin(3t) = 7sin(3*(t+T))
assuming that they equal each other:
3*t = 3*(t+T)
solving for T gives:
T = 0
but T = 0 = 2∏
am I right in assuming that it is periodic with a period of 2∏ or since T = 0 is it aperiodic?
x(t) = x(t+T)
where T is the supposed period.An example equation would be:
x(t) = 7sin(3t)
I would set up the equation like so:
7sin(3t) = 7sin(3*(t+T))
assuming that they equal each other:
3*t = 3*(t+T)
solving for T gives:
T = 0
but T = 0 = 2∏
am I right in assuming that it is periodic with a period of 2∏ or since T = 0 is it aperiodic?
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