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Homework Statement
My brain hasn't been working lately so if you see something weird in my proof pardon me and advice me against it.
So the problem states:
Show that an even degree polynomial has either an absolute max or min.
Homework Equations
The Attempt at a Solution
Let f(x) be an even degree poly.
Without loss of generality suppose, [itex] \displaystyle\lim_{x \to\infty} f(x) = \infty[/itex].It is obvious that f(x) is not bounded above, so we have no absolute max in this case.
Let [itex] S = [tex]\left\{x : f(x) \leq 0\right\}[/tex]
S is bounded below since f(x) does not go to [itex] -\infty[/itex].
Let [itex] A = \left\{f(x) :x \in S\right\} [/itex]
A is bouded below since f(x) does not go to [itex] -\infty[/itex].
LEt [itex] \beta = infA[/itex].
For every n there exist [itex] x_n \in [a,b] [/itex] such that [itex] \beta \leq f(x_n) < B + \frac{1}{n} [/itex]
(Note a and b exist because of the f(x) does not go to [itex] -\infty[/itex] and f(x) goes to [itex] \infty[/itex] respectively. )
[tex] f(x_n) \rightarrow \beta [/tex]
There exist [itex] x_{n_k} \rightarrow x[/tex] since [itex] x_n[/tex] is bounded.
Also [itex] x \in [a,b] [/tex]By uniqueness of limits and continuity [itex] f(x_{n_k}) \rightarrow f(x) = \beta [/itex]
For the case where f(x) > 0 for all x and f(x) still goes to infinity as x goes to infinity I used the set [itex] S = \left\{x : f(x) \leq f(0)= a_0 \right\}[/itex] then the proof is analogous.
Also the proof is the same when [itex] \displaystyle\lim_{x \to\infty} f(x) = -\infty[/itex] except we find a max instead.
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