Prove that e^ia + 2e^ib = re^ic?

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SUMMARY

The discussion centers on proving the equation eia + 2eib = reic, utilizing the relationship r2 = 5 + 4cos(a - b) and tan(c) = (sin(a) + 2sin(b)) / (cos(a) + 2cos(b)). Participants explore the expansion of the exponential terms and the implications of the arctangent function in the context of complex numbers. The challenge lies in effectively manipulating these equations to establish the proof.

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  • Familiarity with trigonometric identities and their applications
  • Knowledge of the properties of the tangent function
  • Ability to manipulate and solve equations involving imaginary numbers
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Students studying complex analysis, mathematicians working with trigonometric identities, and anyone interested in solving equations involving complex numbers and exponential functions.

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Homework Statement


Prove that e^ia + 2e^ib = re^ic?



Homework Equations


given : r^2 = 5 + 4cos( a - b )
tan c = (sin a + 2 sin b) / (cos a + 2 cos b)
i is imaginary number


The Attempt at a Solution


I tried to expand e^ia + 2e^ib and make it equal to r^2
but I don't know what to do with the tan c
 
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tommykhoa said:
but I don't know what to do with the tan c
What's wrong with arctangent?
 

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