Prove that: F(x1,x2, xn)<=min Fi(xi)

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SUMMARY

The discussion centers on proving the inequality F(x1, x2, ..., xn) ≤ min Fi(xi), where F represents a cumulative distribution function (CDF) for the variables x1 through xn. The participants emphasize the intuitive nature of this inequality but express difficulty in formulating a rigorous mathematical proof. The conversation suggests that a detailed examination of the probabilities involved in the CDFs is essential for establishing the validity of the statement.

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aashish.v
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1. Prove that: F(x1,x2,...xn)<=min Fi(xi)

Where F is a DF on (x1...xn)

I know that this is very intuitive. But I am not able to find proper mathematical argument for that.
 
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Assuming "DF" means (cumulative) distribution function, try writing out the left and right sides in terms of probabilities.
 
aashish.v said:
1. Prove that: F(x1,x2,...xn)<=min Fi(xi)

Where F is a DF on (x1...xn)

I know that this is very intuitive. But I am not able to find proper mathematical argument for that.

Check your PMs. You *must* show your efforts before we can offer tutorial help.
 

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