Prove that Hermitian/Skew Herm/Unitary Matrix is a Normal Matrix

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SUMMARY

The discussion centers on proving that Hermitian, Skew Hermitian, and Unitary matrices are all classified as Normal matrices. A Normal matrix satisfies the condition A*A = AA*. Hermitian matrices are defined by the property A = A*, while Skew Hermitian matrices satisfy A = -A*. The participants emphasize the importance of recognizing these definitions to establish the proof effectively.

PREREQUISITES
  • Understanding of Normal matrices and their properties
  • Familiarity with Hermitian matrices and their definitions
  • Knowledge of Skew Hermitian matrices and their characteristics
  • Basic matrix multiplication and properties
NEXT STEPS
  • Study the properties of Unitary matrices and their relation to Normal matrices
  • Explore proofs involving matrix multiplication and commutativity
  • Learn about the implications of matrix adjoints in linear algebra
  • Investigate examples of each matrix type to solidify understanding
USEFUL FOR

Students of linear algebra, mathematicians, and anyone studying matrix theory or preparing for advanced mathematics courses.

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Homework Statement


Show the proof that the following are all Normal Matrices
a. Hermitian
b. Skew Hermitian
c. Unitary

Homework Equations



Normal Matrices: A*A=AA*
Hermitian Matrices: A=A* or aij=a*ji
Skew Hermitian Matrices A=-A* or aij=-a*ji

The Attempt at a Solution



So far I have tried using the above information for Hermitian Matrices to try and prove that A*A=AA* but I keep getting answers I know not to be correct. I would appreciate a nudge in the correct direction so I can quit pulling my hair out. I have a feeling when I find the correct proof it will be quite obvious, but right now I am just missing something.
 
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If A is hermitian then A*=A. A*A=AA=AA*. How are you trying to do it?
 
I was trying to do it much more in depth using amn. It never occurred to me to use the basic matrix itself. Like I said, it was right in front of me. Thank you for the help!
 

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