Prove that SU(n) is closed and bounded

  • #1

Homework Statement



Prove that SU(n) is closed and bounded

Homework Equations





The Attempt at a Solution



So in order to prove this, I first mapped SU(n) to be a subset of [tex]R^{{2n}^2}[/tex].

To prove the closed portion, I tried mapping a sequence in SU(n) to a sequence in [tex]R^{{2n}^2}[/tex]. However, I have trouble showing that the limit of that sequence in SU(n) is still within SU(n).

For the bounded portion, I got to the point in needing to find a radius, r, such that SU(n) is a subset of that ball of radius around the origin in [tex]R^{{2n}^2}[/tex].

However, its at these points that I'm having trouble for both problems in finding the intuition to solve them

Thanks in advance for the help!
 
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Answers and Replies

  • #2
1,444
4

Homework Statement



Prove that SU(n) is closed and bounded

Homework Equations





The Attempt at a Solution



So in order to prove this, I first mapped SU(n) to be a subset of R^{2n}^2.

And how did you do it? Can you describe this subset explicitly?
 
  • #3
Oh, so since SU(n) consists of [tex] n \times n [/tex] matrices with complex entries, I first mapped each with points in [tex]C^{n^2}[/tex].

And consequently, each of the points in [tex]C^{n^2}[/tex] can be mapped to another point in [tex]R^{{2n}^2}[/tex] since each entry of SU(n) can be written as [tex]a + bi[/tex]. So we have coordinates of [tex](a_{1,1}, b_{1,1}, ..., a_{i,j} , b_{i,j}, ...)[/tex] and 2n of such so... each point is mapped in [tex]R^{{2n}^2}[/tex]
 
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  • #4
1,444
4
And what are the equations that describe SU(n) as a set of matrices. What are the equations for U(n) and what is the equation that adds the "S" in front.
 

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