1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Prove that the lim as x goes to a of sqrtx = sqrta

  1. Sep 20, 2009 #1
    can i get some help on proving this limit?
  2. jcsd
  3. Sep 21, 2009 #2


    User Avatar
    Homework Helper

    start with
  4. Sep 21, 2009 #3
    I think it would be very helpful if you guys used latex

    The question should be

    Proove that [tex]\lim {x \rightarrow a} \sqrt{x} = \sqrt{a}[/tex]

    And the first reply should be

    start with

    For basic things like this, latex only takes about a minute to learn and it VERY much easier to read :)
  5. Sep 21, 2009 #4


    User Avatar
    Science Advisor

    In order to prove that "[itex]\lim_{x\to a}\sqrt{x}= \sqrt{a}[/itex], you need to prove that "Given [itex]\epsilon> 0[/itex], there exist [itex]\delta> 0[/itex] such that if [itex]|x- a|< \delta[/itex] then [itex]|\sqrt{x}-\sqrt{a}|< \epsilon[/itex]".

    Start from the second inequality and show (using the above hint) that you can find such a [itex]\delta[/itex].
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook