What is the Derivative of y = √x at x = 1?

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SUMMARY

The derivative of the function y = √x at x = 1 can be calculated using the limit definition of the derivative. The formula applied is lim x -> a = (f(x) - f(a)) / (x - a). By substituting f(x) with √x and simplifying the expression (√x - 1) / (x - 1), the derivative can be evaluated effectively. The final simplification leads to the result of 1/2, confirming that the derivative at x = 1 is 1/2.

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fiziksfun
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I was asked to find the derivative of y=sqrtx at x=1

I need to use the formula

lim x -> a = f(x) - f(a) / (x-a) to find the derivative at x=1

I have..

sqrtx - 1 / (x - 1) BUT i can't simply it from there. Help!

THANKSZ.
 
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Okay:
[tex]\frac{\sqrt{x}-1}{x-1}=\frac{\sqrt{x}+1}{\sqrt{x}+1}\frac{\sqrt{x}-1}{x-1}=\frac{(\sqrt{x}+1)(\sqrt{x}-1)}{x-1}\frac{1}{\sqrt{x}+1}[/tex]
Does that help you a bit?
 

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