Prove the following limits when c ∈ N (analysis help):

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The discussion revolves around proving two limits involving natural numbers. For the first limit, participants express confusion about their approach, particularly when trying to eliminate radicals in the numerator and denominator. The consensus highlights that simply multiplying by a conjugate does not work for higher roots and emphasizes the need for a proper epsilon-delta proof rather than just evaluating the limits. Additionally, there is a suggestion to clarify with the professor whether other theorems can be used for the proof. Overall, the thread underscores the importance of understanding the mathematical principles behind limit proofs.
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Homework Statement


Prove that when c ∈ N:

a)
lim [\sqrt[c]{1+x} - 1]/x = 1/c
x->0

b)
lim [(1+x)^r - 1]/x = r
x->0

,where r = c/n


The Attempt at a Solution



My approach for a and b are pretty similar, i get stuck at the same point.

For a, i multiplied the numerator and the denominator by [(1+x)^(1/c) + 1] to get rid of the radical on top. This left me with:

Lim 1/[(1+x)^(1/c)+1]
x->0

This is where I am stuck, if i find the limit of the numerator and divide it by the limit of the denominator, i don't get 1/c. So I am clearly doing something wrong.

As for part c, i pretty much use the same approach and get:

Lim 1/[(1+x)^(r)+1]
x->0

which also doesn't lead to the answer.

Please help.
 
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cooljosh2k2 said:

Homework Statement


Prove that when c ∈ N:

a)
lim [\sqrt[c]{1+x} - 1]/x = 1/c
x->0

b)
lim [(1+x)^r - 1]/x = r
x->0

,where r = c/n


The Attempt at a Solution



My approach for a and b are pretty similar, i get stuck at the same point.

For a, i multiplied the numerator and the denominator by [(1+x)^(1/c) + 1] to get rid of the radical on top.
This works for square roots, but not for cube roots, fourth roots, etc.

(a - b)(a + b) = a2 - b2
If a is the square root of something, a2 will have the radical eliminated.

(a - b)(a2 + ab + b2 = a3 - b3
This time, if a is the cube root of something, a3 will have the radical eliminated.

(a - b)(a3 +a2b + ab2 + b3) = a4 - b4
In this example, if a is the fourth root of something, a4 will have the radical eliminated.

Notice that there is a pattern here.
cooljosh2k2 said:
This left me with:

Lim 1/[(1+x)^(1/c)+1]
x->0

This is where I am stuck, if i find the limit of the numerator and divide it by the limit of the denominator, i don't get 1/c. So I am clearly doing something wrong.

As for part c, i pretty much use the same approach and get:

Lim 1/[(1+x)^(r)+1]
x->0

which also doesn't lead to the answer.

Please help.
 
Mark44 said:
This works for square roots, but not for cube roots, fourth roots, etc.

(a - b)(a + b) = a2 - b2
If a is the square root of something, a2 will have the radical eliminated.

(a - b)(a2 + ab + b2 = a3 - b3
This time, if a is the cube root of something, a3 will have the radical eliminated.

(a - b)(a3 +a2b + ab2 + b3) = a4 - b4
In this example, if a is the fourth root of something, a4 will have the radical eliminated.

Notice that there is a pattern here.

Im confused, isn't that what i did? I removed the radical in the numerator by multiplying it by the the square root + 1, but it then leaves me with a radical in the denominator. I still don't understand how it would give me for a) a limit of 1/c.
 
Are you trying to prove or "evaluate" these limits because I don't see any epsilons and deltas.
 
╔(σ_σ)╝ said:
Are you trying to prove or "evaluate" these limits because I don't see any epsilons and deltas.

The question says "prove that...", but doesn't specify if i have to use epsilons and deltas or can use another theorem such as squeeze theorem, ratio theorem, etc to prove the limit.
 
Maybe you should ask your professor because what you are doing now is verifying not proving since you are already given the limits.
 
Mark44 said:
This works for square roots, but not for cube roots, fourth roots, etc.

(a - b)(a + b) = a2 - b2
If a is the square root of something, a2 will have the radical eliminated.

(a - b)(a2 + ab + b2 = a3 - b3
This time, if a is the cube root of something, a3 will have the radical eliminated.

(a - b)(a3 +a2b + ab2 + b3) = a4 - b4
In this example, if a is the fourth root of something, a4 will have the radical eliminated.

Notice that there is a pattern here.

cooljosh2k2 said:
Im confused, isn't that what i did? I removed the radical in the numerator by multiplying it by the the square root + 1, but it then leaves me with a radical in the denominator. I still don't understand how it would give me for a) a limit of 1/c.

You CANNOT remove the radical in the numerator if you multiply the "c"th root of 1 + x by the square root of 1 + x. Also, as ╔(σ_σ)╝ points out, you need to prove that the limits are as given, not just evaluate them. That will entail using an epsilon-delta proof.
 

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