Proving 1 ppm = 1 mg/L: Conflicting Equations?

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SUMMARY

The discussion centers on the equivalence of 1 ppm (parts per million) and 1 mg/L (milligram per liter) in aqueous solutions. The user presents conflicting equations regarding the definitions of ppm and mg/L, ultimately concluding that 1 ppm equals 1 mg/L when the density of water is assumed to be approximately 1 kg/L. The confusion arises from the interpretation of mass ratios and the conversion factors involved in these definitions.

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  • Understanding of concentration units, specifically ppm and mg/L.
  • Basic knowledge of mass and volume relationships in aqueous solutions.
  • Familiarity with the concept of density, particularly for water (1 kg/L).
  • Ability to manipulate and interpret mathematical equations related to concentration.
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  • Research the derivation of concentration units, focusing on ppm and mg/L conversions.
  • Explore the implications of density on concentration calculations in different solvents.
  • Learn about the significance of mass ratios in chemical solutions.
  • Investigate common misconceptions regarding concentration units in scientific literature.
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Chemistry students, environmental scientists, and professionals involved in laboratory analysis or quality control who need to understand concentration measurements in aqueous solutions.

Jimmy25
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My text claims that 1 ppm = 1 mg/L. I tried to prove this for myself but I seem to be stuck. This is what I have so far:

1 mg(solute)/L(solvent) = 1 mg(solute) / 1*10^6 mg(solvent)

But:

C(ppm) = (mass solute)/(mass solvent) *10^6 ppm

These seem to be in conflict, what am I not seeing?
 
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1 ppm = 1 mg/L for water solutions, when you can assume mass of 1L to be close to 1 kg.
 
Yes, but how can it be proved?
 
1 mg/1 kg = 10-6, I am not sure where the problem is.
 

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