Proving 1 ppm = 1 mg/L: Conflicting Equations?

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Homework Help Overview

The discussion revolves around the equivalence of 1 ppm and 1 mg/L, particularly in the context of solutions, and the apparent conflict in equations related to this relationship.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to reconcile different equations related to concentration and questions the validity of their findings. Some participants clarify that the equivalence holds under specific assumptions, while others seek a formal proof of the relationship.

Discussion Status

Participants are exploring the conditions under which 1 ppm equals 1 mg/L, with some providing insights on assumptions regarding the density of water. The discussion is ongoing, with various interpretations being examined.

Contextual Notes

There is an implicit assumption that the density of the solution is similar to that of water, which may not hold in all cases. The original poster's confusion stems from differing interpretations of the equations provided.

Jimmy25
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My text claims that 1 ppm = 1 mg/L. I tried to prove this for myself but I seem to be stuck. This is what I have so far:

1 mg(solute)/L(solvent) = 1 mg(solute) / 1*10^6 mg(solvent)

But:

C(ppm) = (mass solute)/(mass solvent) *10^6 ppm

These seem to be in conflict, what am I not seeing?
 
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1 ppm = 1 mg/L for water solutions, when you can assume mass of 1L to be close to 1 kg.
 
Yes, but how can it be proved?
 
1 mg/1 kg = 10-6, I am not sure where the problem is.
 

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