Proving a Function is Riemann Integrable

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Homework Help Overview

The problem involves proving that the function h(x) = max{f(x), g(x)} is Riemann integrable on the interval [a, b], given that f and g are integrable functions on the same interval. The discussion centers around the definitions and properties of integrability in the context of maximum functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of integrability and explore how to express max(f, g) in terms of known integrable functions. There are attempts to relate max functions to absolute values and to derive expressions that could demonstrate integrability.

Discussion Status

The discussion is ongoing, with participants sharing hints and exploring various approaches to express the maximum function. Some participants are questioning the applicability of known theorems and are attempting to derive new expressions to support their arguments.

Contextual Notes

There is a mention of a theorem regarding the integrability of absolute values, and participants are trying to connect this to the problem at hand. The original poster expresses uncertainty about how to apply these concepts effectively.

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Homework Statement



Let f, g : [a, b] \rightarrow R be integrable on [a, b]. Then, prove that h(x) = max{f(x), g(x)} for
x \in [a, b] is integrable.
1

Homework Equations



Definition of integrability: for each epsilon greater than zero there exists a partition P so that U(f,P)-L(f,P)<epsilon

The Attempt at a Solution




Ok i have absolutley no clue how to do this one. The following graph is how i think the function would look : http://i31.photobucket.com/albums/c373/SNOOTCHIEBOOCHEE/Graph2.jpg

Sorry about the crude drawing, but the very light blue would be h(x)

But i honest to god can't see a way to make U(f,P)-L(f,P)<epsilon a true statement

Thanks in advance
 
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Hint: Prove that if f is integrable then so is |f|.

Why does this help?
 
I know that that is a theorem in the book, but i don't see how its applicable here. i also know that |Integral(f)| < Integral(|f|) comes from that statement.
 
Last edited:
Try writing max(f,g) in terms of absolute values. To get a feel for this, try to find such an expression for max(f,0).
 
how do you mean in absolute values?

like max(f,g)<max(|f|,|g|)?

edit: guess not

im trying to figure out this for h(x)= max(f,0)

so we know h(x) = f if f is positive and 0 else.

but i can't figure this out for the other thing.
 
max(f,0) = (|f| + f)/2
 
I see where this argument is going. Basically you are gunna describe h(x) as a sum of absolute values of functions we already know are integrable, therefore the result is integrable.

Now to figure out max(f,g)...
 
sorry for the tripple post. but i got a little bit farthermax(f,g)= [(g+|g|)+ (f+|f|)] /2 - min(f,g)

but then i got to figure out how to describe the min function...
 
Try to think about f-g and f+g.
 
  • #10
ok you I am not getting this

[(g+|g|)+ (f+|f|)] /2 = f+g if f and g are the same sign
 
  • #11
I really don't know how to give you any more hints that don't involve giving you the answer! Maybe try thinking about why (|f|+f)/2 gives us max(f,0). Try to sleep on it.
 

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