Proving angles are equal in a triangle in a circle.

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SUMMARY

The discussion centers on proving that angles CAB and CBA are equal in a triangle inscribed in a circle. The proof utilizes the inscribed angle theorem and the alternate segment theorem, establishing that the angles are equal due to their relationship with the arcs AC and CB. It concludes that triangle CBA is isosceles, as both angles CAB and CBA are equal, confirming the properties of angles in a circle.

PREREQUISITES
  • Understanding of the inscribed angle theorem
  • Familiarity with the alternate segment theorem
  • Knowledge of basic properties of isosceles triangles
  • Ability to interpret geometric diagrams involving circles and angles
NEXT STEPS
  • Study the inscribed angle theorem in detail
  • Explore the alternate segment theorem and its applications
  • Practice problems involving isosceles triangles and their properties
  • Learn about the relationships between angles and arcs in circle geometry
USEFUL FOR

Students of geometry, mathematics educators, and anyone interested in the properties of angles and triangles within circle geometry.

markosheehan
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View attachment 6094

hi can someone help me work this out. i think it has something to do with the exterior angle of a triangle is equal to the sum of the interior angles but i can't work it.
 

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Prove that $\angle CAB=\angle CBA$ by connecting these angles to measures of arcs using the inscribed angle theorem and its corollary about tangent lines.
 
how do you know the arcs AC and CB are the same
 
Last edited:
markosheehan said:
how do you know the arcs AC and CB are the same

Are you familiar with the Alternate Segment theorem, which states that

The angle between the tangent and chord at the point of contact is equal to the angle in the alternate segment.

View attachment 6099

So now do you see a similarity between the angle marked in blue in the above diagram & the angle marked in blue in your diagram.

$\therefore$ It can be said that $\angle CAT = \angle CBA$ using alternate segment theorem

Now what can be said about the triangle CBA using it's angles?
 

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It's isosceles
 

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