Proving Boundedness of Continuous Functions in [a,+∞] with Limits

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Homework Help Overview

The discussion revolves around proving that a continuous function \( f(x) \) is bounded on the interval \([a, +\infty)\) given that the limit of \( f(x) \) exists as \( x \) approaches \( +\infty \).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the limit at infinity and continuity of the function. There is a discussion about the choice of epsilon in the limit definition and its relevance to the proof of boundedness.

Discussion Status

Some participants have offered insights into the relationship between the limit and boundedness, while others are seeking clarification on specific choices made in the reasoning process. The conversation appears to be productive, with various interpretations being explored.

Contextual Notes

There is a mention of potential confusion regarding the interval of boundedness and the specific choice of epsilon in the limit definition. Participants are also considering the implications of continuity on boundedness.

sedaw
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need to prove that f(x) bounded if f(x) continuous in [a,+infinite] and if there's a limit while x goes to +infinite.


I would really appreciate any kind of help !
 
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sedaw said:
need to prove that f(x) bounded if f(x) continuous in [a,+infinite] and if there's a limit while x goes to +infinite.


I would really appreciate any kind of help !

I assume you mean prove that f is bounded in [a, infinity). Otherwise, it is not true. Let the limit be L. By definition of limit at infinity, that means that there exist some R such that if x> R, |f(x)- L|< 1 so for x> R, L-1< f(x)< L+1. Further since f(x) is continuous, f is bounded on the close, bounded interval [0, R]. Put those two together.
 
hello HallsofIvy ! , " I assume you mean prove that f is bounded in [a, infinity)."

that is right , i don't understand why did u choose epsilon=1 is it necessary ?

TNX!
 
Since the problem is only to prove that f is bounded, you can choose [itex]\epsilon[/itex] to be any (non-zero) number. "1" happened to be convenient.

If |f(x)|< B on [0, R] and |f(x)|< 1 on [R, infinity), what is a bound on f?
 

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