Proving Continuity of f(x,y) = y/(1+x2) Using Delta-Epsilon Bound

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SUMMARY

The discussion focuses on proving the continuity of the function f(x,y) = y/(1+x²) at the point (0,0) using the delta-epsilon definition. Participants emphasize the importance of establishing bounds for the denominator, specifically 1+x². A lower bound of 1 is confirmed, leading to an upper bound of 1 for the expression 1/(1+x²). This establishes that the function is continuous at the specified point.

PREREQUISITES
  • Understanding of the delta-epsilon definition of continuity
  • Familiarity with basic calculus concepts
  • Knowledge of limits and bounds in mathematical analysis
  • Experience with functions of multiple variables
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  • Study the delta-epsilon definition of continuity in depth
  • Explore the concept of limits in multivariable calculus
  • Learn about bounding techniques for functions
  • Investigate continuity proofs for other functions
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Mathematics students, educators, and anyone interested in understanding the continuity of functions in multivariable calculus.

trap101
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Use the delta-epsilon definition to prove f(x,y) = y/(1+x2) is continuous at (0,0)Attempts:So I'm doing some work and my main issue is finding a bound for the denominator of 1+x2:

So work wise I have something looking like:

\delta/(|1| + |x2| ). How could I found a good bound?
 
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trap101 said:
Use the delta-epsilon definition to prove f(x,y) = y/(1+x2) is continuous at (0,0)

Attempts:

So I'm doing some work and my main issue is finding a bound for the denominator of 1+x2:

So work wise I have something looking like:

\delta/(|1| + |x2| ). How could I found a good bound?
An lower bound for 1+x2 is definitely 1.

That makes and upper bound of 1 for 1/(1+x2) .
 
thanks
 

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