Proving Every Infinite Set Has An Infinite Countable Subset

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SUMMARY

Every infinite set contains an infinite countable subset, which can be demonstrated through the construction of a bijection from the natural numbers to the subset. Specifically, for an infinite set S, one can select elements iteratively, starting with an arbitrary element s1 from S, and then choosing subsequent elements sn from the remaining elements of S, ensuring that no previously selected elements are included. This method is not applicable to finite sets, as they lack the necessary elements to form an infinite countable subset.

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Doom of Doom
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So, the task is to prove: Every infinite set has a infinite countable subset.


2. A set [tex]S[/tex] is countable if there exists a bijection [tex]\phi: \mathbb{N}\rightarrow X[/tex]


The Attempt at a Solution

 
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You can easily construct a countable subset [itex]\{s_1,s_2,\dots\}[/itex] wiht [itex]s_1,s_2,\dots[/itex] being elements of S.

Let [itex]s_1[/itex] be some element of S. Let inductively [itex]s_n[/itex] be some element of [itex]S-\{s_1,\dots,s_{n-1}\}[/itex].

Can you show that this works for any infinite set, and that it does not work for any finite set?
 
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