Proving Integer Eigenvalues of Matrix A

  • Thread starter Thread starter hadizainud
  • Start date Start date
  • Tags Tags
    Eigenvalues
Click For Summary

Homework Help Overview

The discussion revolves around proving that a 2x2 matrix A, defined with integer elements a, b, c, and d such that a+b=c+d, has integer eigenvalues, specifically λ_1 = a+b and λ_2 = a-c.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the computation of eigenvalues for a 2x2 matrix and the implications of the given conditions. Some suggest using the definition of eigenvalues rather than calculating them directly. Others mention properties of eigenvalues related to the determinant and trace of the matrix.

Discussion Status

Participants are exploring various methods to approach the problem, including definitions and properties of eigenvalues. There is no explicit consensus, but several lines of reasoning and methods have been proposed to guide the discussion.

Contextual Notes

Some participants note the importance of the relationship a+b=c+d in simplifying the problem, while others question the necessity of calculating eigenvalues directly.

hadizainud
Messages
15
Reaction score
0

Homework Statement



Prove: If a, b, c, and d are integers such that a+b=c+d, then
A=
[a b]​
[c d]​
has integer eigenvalues, namely,[itex]λ_1{}[/itex]=a+b and [itex]λ_2{}[/itex]=a-c

Homework Equations



No relevant equation.

The Attempt at a Solution



No idea :(
 
Physics news on Phys.org
Do you know how to compute the eigenvalues of a 2x2 matrix? Try that first before applying the additional information given in the problem.
 
You don't really need to calculate the eigenvalues, you are only asked to show that a+b and a- c are eigenvalues- and to do that you use the definition of "eigenvalue".

That is, do there exist values, x and y, such that
[tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}\begin{bmatrix}x \\ y\end{bmatrix}= (a+b)\begin{bmatrix}u \\ v\end{bmatrix}[/tex]
or values u and y such that
[tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}\begin{bmatrix}u \\ v\end{bmatrix}= (a-b)\begin{bmatrix}u \\ v\end{bmatrix}[/tex]
?
 
Welcome to PF, hadizainud! :smile:

The methods of fzero and HallsofIvy will bring you your answer.
Just for fun, here's yet another method.

The product of the eigenvalues is equal to the determinant.
The sum of the eigenvalues is equal to the trace.
In a quadratic equation the roots are uniquely identified by their product and their sum.
Use a+b=c+d to eliminate d in your equations.
 
I like Serena said:
Welcome to PF, hadizainud! :smile:

The methods of fzero and HallsofIvy will bring you your answer.
Just for fun, here's yet another method.

The product of the eigenvalues is equal to the determinant.
The sum of the eigenvalues is equal to the trace.
In a quadratic equation the roots are uniquely identified by their product and their sum.
Use a+b=c+d to eliminate d in your equations.

Hmm, that's cute :smile:
 

Similar threads

Replies
2
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
10
Views
3K