Proving Integral Equation: f(x)= O(x)

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SUMMARY

The discussion focuses on proving the integral equation defined by the functions f(x) and g(x), specifically demonstrating that f(x) = O(x). The integral equation is expressed as g(x) = ∫₀^∞ K(yx)f(y)dy. By applying a change of variable yx = t, the inequality g(x) ≤ C/x² ∫₀^∞ K(t)t dt is derived, contingent on the existence of the integral. The analysis assumes that K(t) remains positive over the interval [0, ∞) and highlights the necessity of understanding the order of g or K for further conclusions.

PREREQUISITES
  • Understanding of integral equations
  • Familiarity with Big O notation
  • Knowledge of change of variables in integrals
  • Concept of positive functions over intervals
NEXT STEPS
  • Study the properties of integral equations in functional analysis
  • Learn about asymptotic analysis and Big O notation
  • Explore the implications of positive kernels in integral equations
  • Investigate convergence criteria for improper integrals
USEFUL FOR

Mathematicians, researchers in functional analysis, and students studying integral equations and asymptotic behavior will benefit from this discussion.

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let be the functions f(x) and g(x) defined by an integral equation

[tex]g(x)= \int_{0}^{\infty}dy K(yx)f(y)dy[/tex]

then i want to prove that for example [tex]f(x)= O(x)[/tex]

then using a change of varialbe yx=t i manage to put

[tex]g(x) \le \frac{C}{x^{2}} \int_{0}^{\infty}dtK(t)t[/tex]

if the last integral exists , then a simple condition is that there will be a constant so [tex]x^{2} g(x) \le A[/tex] i assume K(t) is ALWAYS positive on the interval [0,oo)
 
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It's difficult to decide unless one knows the order of g or K.
 

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