Proving Irreducibility of Polynomials in Fields

  • Thread starter Thread starter playa007
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on proving the irreducibility of polynomials in fields, specifically examining the polynomial f(x) = a_0 + a_1x + a_2x^2 + ... + a_nx^n in k[x]. It asserts that if f(x) is irreducible, then the polynomial a_n + a_{n-1}x + ... + a_0x^n is also irreducible. The participants explore alternative approaches to proving this property, noting that reversing coefficients does not yield a well-defined function and questioning the applicability of Eisenstein's Criterion in this context.

PREREQUISITES
  • Understanding of polynomial irreducibility in field theory
  • Familiarity with the structure of fields and polynomial rings
  • Knowledge of Eisenstein's Criterion for irreducibility
  • Basic algebraic manipulation and function properties
NEXT STEPS
  • Study the implications of polynomial transformations in field theory
  • Research alternative irreducibility tests beyond Eisenstein's Criterion
  • Explore the concept of polynomial reversibility and its mathematical implications
  • Learn about the relationship between polynomial degree and irreducibility in finite fields
USEFUL FOR

Mathematicians, algebra students, and researchers interested in field theory and polynomial irreducibility, particularly those looking to deepen their understanding of polynomial properties and proofs.

playa007
Messages
25
Reaction score
0

Homework Statement


Let k be a field, and let f(x) = a_0 + a_1x +a_2x^2 +...+a_nx^n in k[x] having degree n. If f(x) is irreducible, then so is a_n + a_n-1x+...+a_0x^n


Homework Equations





The Attempt at a Solution


A function that "reverses" the coefficients is not a well-defined function so it is necessary to use another approach. I'm wondering how this can be done, I'm pretty sure Eisenstein's Criterion isn't of much use here.

Any help would be highly appreciated.
 
Physics news on Phys.org
playa007 said:
A function that "reverses" the coefficients is not a well-defined function
?
Is it any help that your second function is f(y)/y^n where y = 1/x ?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K