Proving Kp will remain constant if total press. is doubled

[CroSinus]

Homework Statement

Is there a way I can prove (mathematically) that Kp for the chemical reaction: H2(g) + I2(s) <--> 2HI(g) will remain constant if I double the total pressure of the mixture?

Homework Equations

[/B]
H2(g) + I2(s) <--> 2HI(g)

The Attempt at a Solution

If I write the expression for Kp from the above reaction I get: Kp = p^2(HI) / p(H2). Now, if I double the total pressure of the mixture I get K'p = 2Kp. However, I know from the theory that Kp is independent of the total pressure of the mixture. But is there a way I can prove it mathematically? Thanks in advance for your help.

 

[Bystander]

Kp = p^2(HI) / p(H2) ... get K'p = 2Kp

It appears that you're trying to preserve the degree of completion rather than K_p as a function of pressure. Remember that K_p is in terms of partial pressures.

 

[Borek]

That Kp is a constant can be only proved experimentally, not mathematically.