Finding Kp given the final equilibrium pressure

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SUMMARY

The discussion focuses on calculating the equilibrium constant Kp for the reaction S(s) + 2CO(g) <--> SO2(g) + 2C(s) given a final equilibrium pressure of 1.03 atm. The user correctly identifies that Kp is determined using the formula Kp = P(products)/P(reactants), but mistakenly attempts to apply it without considering the stoichiometry of the reaction. The final equilibrium pressure is crucial for determining the extent of the reaction, which is necessary to calculate Kp accurately.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with the equilibrium constant expression Kp
  • Knowledge of stoichiometry in chemical reactions
  • Basic principles of gas behavior and pressure
NEXT STEPS
  • Study the derivation and application of the equilibrium constant Kp
  • Learn how to use stoichiometry to relate changes in pressure to reaction progress
  • Explore the concept of partial pressures in gas reactions
  • Review examples of equilibrium calculations involving solid and gaseous reactants/products
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical equilibrium analysis will benefit from this discussion, particularly those focusing on gas-phase reactions and equilibrium constants.

ebunny91
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Homework Statement



When two moles of CO are introduced into a vessel containing solid sulfur, the final equilibrium pressure is 1.03 atm. Determine Kp for the reaction:

S(s) + 2CO(g) <--> SO2(g) + 2C(s)



Homework Equations



Kp=P(products)/P(reactants)

Mole Fraction = mole of A/ total moles



The Attempt at a Solution



I know Kp=P(products)/P(reactants)

So I have Kp=[SO2]/[CO2]^2, I left the S and the C out because they are solids.

I am not sure what to do with the final equilibrium pressure.
 
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Is it all data given? If so, looks to me like there is not enough information to solve the problem.

Usually final pressure can be used to find out how far reaction proceeded (using stoichiometry), but it can't be done in this case.
 

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