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Proving Kp will remain constant if total press. is doubled

  1. Mar 9, 2015 #1
    1. The problem statement, all variables and given/known data
    Is there a way I can prove (mathematically) that Kp for the chemical reaction: H2(g) + I2(s) <--> 2HI(g) will remain constant if I double the total pressure of the mixture?

    2. Relevant equations
    H2(g) + I2(s) <--> 2HI(g)

    3. The attempt at a solution
    If I write the expression for Kp from the above reaction I get: Kp = p^2(HI) / p(H2). Now, if I double the total pressure of the mixture I get K'p = 2Kp. However, I know from the theory that Kp is independent of the total pressure of the mixture. But is there a way I can prove it mathematically? Thanks in advance for your help.
     
  2. jcsd
  3. Mar 10, 2015 #2

    Bystander

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    It appears that you're trying to preserve the degree of completion rather than Kp as a function of pressure. Remember that Kp is in terms of partial pressures.
     
  4. Mar 10, 2015 #3

    Borek

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    That Kp is a constant can be only proved experimentally, not mathematically.
     
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