Proving Limit of r/n as n Approaches Infinity

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SUMMARY

The limit of \( r^{1/n} \) as \( n \) approaches infinity is proven to be 1 for any \( r > 0 \). The proof involves demonstrating that for any \( \epsilon > 0 \), there exists an \( n_0 \in \mathbb{N} \) such that \( |r^{1/n} - 1| < \epsilon \). The discussion also touches on a related limit, \( \lim_{n \to 0} r^n = 1 \), and explores the implications of \( 1 < L \leq r^{1/n} \), although clarity on this aspect is lacking.

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Homework Statement



prove that lim(n[tex]\rightarrow\infty[/tex])(r1/n) = 1 for r> 0

The Attempt at a Solution



let [tex]\epsilon[/tex] > 0 be given we need to find n0 [tex]\in[/tex] N such that

[tex]\left|[/tex]r1/n - 1 [tex]\left|[/tex] < [tex]\epsilon[/tex]

but not really sure where to go from here?
 
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What if the problem was a little simpler -- proving that the limit as n approaches 0 of r^n equals 1. How would you go about doing that?
 
1 < L [tex]\leq[/tex] r1/n

implies

1[tex]\leq[/tex] Ln [tex]\leq[/tex] r

i'm not sure how this follows?
 

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