Proving Limits: δ = min(δ1,δ2) Meaning Explained

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The term "δ = min(δ1, δ2)" indicates that δ is defined as the smaller value between δ1 and δ2. This means that if δ1 is less than δ2, then δ equals δ1, and vice versa. In cases where δ1 and δ2 are equal, δ can be set to either value. Understanding this notation is crucial for proving limits in calculus. The discussion emphasizes the importance of clarity in mathematical notation and definitions.
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The chapter I am reading is on proving limits... The terms "δ = min(δ1,δ2)" has came up a few times but what does it mean?

My guess is that the distances δ1 and δ2 are some where in the interval of the distance δ about some x value.
 
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Miike012 said:
The chapter I am reading is on proving limits... The terms "δ = min(δ1,δ2)" has came up a few times but what does it mean?

My guess is that the distances δ1 and δ2 are some where in the interval of the distance δ about some x value.

Typically, min(δ1,δ2) means the smaller of δ1 and δ2, or at least it does in most books and papers. Does your source really not have a glossary of notation?

RGV
 
Ok it says the min of two numbers x and y is denoted min(x,y).. so I am guessing what I posted above that "min(δ1,δ2)" means δ1= δ if δ1<δ2 and vise versa. is that right?
 
Miike012 said:
Ok it says the min of two numbers x and y is denoted min(x,y).. so I am guessing what I posted above that "min(δ1,δ2)" means δ1= δ if δ1<δ2 and vise versa. is that right?
It's the other way around.

δ = δ1 if δ1 is the smaller of the two numbers, and

δ = δ2 if δ2 is the smaller of the two numbers.

If δ1 = δ2, then set δ to either number.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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