Proving Linear Dependence in a Set of Vectors

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Homework Help Overview

The discussion revolves around proving that in a linearly dependent set of vectors, at least one vector can be expressed as a linear combination of the others. The original poster presents a specific scenario involving vectors v_1 through v_k and seeks assistance in demonstrating this property.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the definition of linear dependence, particularly focusing on the coefficients in the linear combination that sums to zero. Questions arise regarding the necessity of at least one coefficient being non-zero and how that affects the ability to express one vector in terms of others.

Discussion Status

Some participants have provided guidance on how to approach the problem, emphasizing the importance of identifying a non-zero coefficient among the linear combination. There is an ongoing exploration of how to express one vector as a combination of the others, with various interpretations being discussed.

Contextual Notes

The original poster has attached an attempt at the problem, and there is an acknowledgment of the need to clarify assumptions regarding the coefficients involved in the linear combination.

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Homework Statement


Suppose v_1,...,v_k is a linearly dependent set. Then show that one of the vectors must be a linear combination of the others.

Homework Equations



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The Attempt at a Solution



I have attached an attempt at the problem. Thank you for help
 

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Your solution says [itex]a_1v_1+ a_2v_2+ a_3v_3+ \cdot\cdot\cdot+ a_nv_n= 0[/itex] and then you go to [itex]v_1= (-1/a_1)(a_2v_2+ a_3v_3+ \cdot\cdot\cdot+ a_nv_n)[/itex]

That's pretty good. The only problem is you don't know that a1 is not 0! If it is you can't solve for v1. What you DO know, from the definition of "dependent", that you didn't say is that at least one of the "ai" is NOT 0. You don't know which one but you can always say "Let "k" be such that ak is not 0". Then what?
 
Thank you. What if i say let k:ak not equal to 0
and v1 is a linear combination of v2,...,vn iff a1=ak
 
You want to show that vk is a linear combination of the rest of the vectors. IOW, that vk is a linear combination of v1, v2, ..., vk-1, vk+1, ..., vn.
 
ok, i think i get it
 

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