Proving Linear Independence of vectors

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SUMMARY

The discussion centers on proving the linear independence of the vectors x1 = (1, 2, -1, 1), x2 = (-1, -1, -1, -1), x3 = (1, 1, 1, 0), and x4 = (-2, -1, -4, -1). The user initially attempted to demonstrate linear dependence using an augmented matrix, which was row-reduced but led to confusion regarding the interpretation of the results. The conclusion drawn is that x1, x3, and x4 are indeed linearly independent, while x2 should be included in the analysis to confirm the independence of the specified vectors.

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zecuria
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Homework Statement



Let x1 = (1, 2, -1, 1), x2 = (-1, -1, -1, -1), x3 = (1, 1, 1, 0), x4 = (-2, -1 -4 -1)

Show that x1, x3 and x4 are linearly independent



Homework Equations





The Attempt at a Solution


Now I used the equation:
ax1+bx2+cx3+dx4=0

Hence forth the augmented matrix of the equation is,

[tex] \begin{pmatrix}<br /> 1 & -1 & 1 & -2 & | & 0\\<br /> 2 & -1 & 1 & -1 & | & 0\\<br /> -1 & -1 & 1 & -4 & | & 0\\<br /> 1 & -1 & 0 & -1 & | & 0<br /> \end{pmatrix}[/tex]

This is row reduced to,

[tex] \begin{pmatrix}<br /> 1 & -1 & 1 & -2 & | & 0\\<br /> 0 & 1 & -1 & 3 & | & 0\\<br /> 0 & 0 & -1 & 1 & | & 0\\<br /> 0 & 0 & 0 & 0 & | & 0<br /> \end{pmatrix}[/tex]

From as there is no leading entry corresponding to d, Setting d = t, the general solution is:

a = -t, b = -2t, c = t, d = t.

And as the number of leading entries =! number of unknowns so the vectors are linearly dependent

This is the point where I get confused as the question asks how they are linearly dependent so I am quite confused at this point

Any help would be most appreciated and thanks in advanced
 
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zecuria said:

Homework Statement



Let x1 = (1, 2, -1, 1), x2 = (-1, -1, -1, -1), x3 = (1, 1, 1, 0), x4 = (-2, -1 -4 -1)

Show that x1, x3 and x4 are linearly independent


You have to show that x1,x2,x4 are linearly independent. Do the Gauss elimination with these three vectors.

ehild
 

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