Proving Measurability and Integrability of a Function on a Product Space

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Homework Help Overview

The problem involves proving the measurability and integrability of a function defined on a product space, specifically the function g on (0,1)×(0,1) derived from a measurable function f on (0,1). The context is rooted in measure theory and Lebesgue integration.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the construction of a new function h using indicator functions to demonstrate the measurability of g. There are questions about the appropriateness of the sets A and B in relation to the domains of the functions involved. Some participants express uncertainty about how to begin the proof and seek suggestions for initial steps.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to establish the measurability of g. Some guidance has been offered regarding the use of indicator functions, but there is no explicit consensus on the correctness of the constructions or the next steps.

Contextual Notes

There are noted technical issues regarding the domains of the functions and the sets being used in the proofs, which may affect the validity of the approaches discussed.

Funky1981
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Homework Statement


Let f : (0,1) —>R be measurable( w.r.t. Lebesgue measure) function in L1((0,1)). Define the function g on (0,1)× (0,1) by

g(x,y)=f(x)/x if 0<y<x<1
g(x,y)=0 if 0<x≤y<1

Prove:
1) g is measurable function (w.r.t. Lebesgue measure in the prodcut (0,1)× (0,1)

2)g is integrable in (0,1)× (0,1)

Homework Equations



I tried to think about the product space but it is not really obvious for me how to begin, Can anyone give me suggestions
 
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Start by showing this:

Let ##(\Omega,\mathcal{B})## is a set with ##\sigma##-algebra.
Let ##A,B\in \mathcal{B}## disjoint, define ##\chi_A## and ##\chi_B## the indicator functions: http://en.wikipedia.org/wiki/Indicator_function#Definition
Let ##f:\Omega\rightarrow \mathbb{R}## and ##g:\Omega\rightarrow \mathbb{R}## be measurable.

Define ##h:\Omega\rightarrow \mathbb{R}## by

h = f\chi_A + g\chi_B

Show that ##h## is measurable.

Use this to show (1).
 
micromass said:
Start by showing this:

Let ##(\Omega,\mathcal{B})## is a set with ##\sigma##-algebra.
Let ##A,B\in \mathcal{B}## disjoint, define ##\chi_A## and ##\chi_B## the indicator functions: http://en.wikipedia.org/wiki/Indicator_function#Definition
Let ##f:\Omega\rightarrow \mathbb{R}## and ##g:\Omega\rightarrow \mathbb{R}## be measurable.

Define ##h:\Omega\rightarrow \mathbb{R}## by

h = f\chi_A + g\chi_B

Show that ##h## is measurable.

Use this to show (1).

So if I take A to be 0<y<x<1, B to be 0<x≤y<1 and construct h = f\chi_A + g\chi_B
consider set {x| h(x)> a} if it is in A then we have h= f then f measurable implies h measurable, is my construction right?
 
Funky1981 said:
So if I take A to be 0<y<x<1, B to be 0<x≤y<1 and construct h = f\chi_A + g\chi_B
consider set {x| h(x)> a} if it is in A then we have h= f then f measurable implies h measurable, is my construction right?

In my post, we had ##A\in \Omega## and ##f## had ##\Omega## as domain.
Now, here is the slight technical issue that ##A\subseteq (0,1)^2##, but this is not the domain of ##f##. So you need to solve this.
 

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