Proving N is a Composite Number: Larson 4.1.8 [SOLVED]

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The discussion focuses on proving that the number N, consisting of 91 ones in decimal notation, is a composite number. The solution utilizes the properties of modular arithmetic, specifically showing that N is divisible by both (107 - 1)/9 and (1013 - 1)/9. The factorization of 91 as 13 * 7 is critical in establishing the divisibility conditions required to demonstrate that N is composite.

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[SOLVED] larson 4.1.8

Homework Statement


Let N be the number which when expressed in decimal notation consists of 91 ones:

1111...1111 = N

Prove that N is a composite number.

Homework Equations





The Attempt at a Solution


If N had an even number n of ones we could use the fact that

\sum_{i=0}^n x^i = (1+x)(x+x^3+x^5+...+x^{n-1}) = N

evaluated at x=10. I tried doing lots of similar tricks for the odd case but nothing seems to factor completely.
 
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Since 91=13*7, then 10^91 - 1 = 0 (mod 10^7 - 1) (and 10^91 - 1 = 0 (mod 10^13 - 1)) - prove this. And since 9N = 10^91 - 1, it follows that N is divisible by (10^7 - 1)/9 (and (10^13 - 1)/9).
 
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